3m^2-11m+9=0

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Solution for 3m^2-11m+9=0 equation: 



3m^2-11m+9=0

a = 3; b = -11; c = +9;
Δ = b2-4ac
Δ = -112-4·3·9
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{13}}{2*3}=\frac{11-\sqrt{13}}{6}
$


$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{13}}{2*3}=\frac{11+\sqrt{13}}{6}
$

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